X^2 Y^2 4x-6y-3=0 153264-The Circle Concentric With X^2+y^2+4x+6y+3=0
6y 99) = 3 (x²4x 4) (y²6y9) = 349 (x2) ²Answer (1 of 5) x²The ordered pair (h,k) is the center of the circle and r is the radius We need to transform the given equation to this form to find the center and radius We will use the completing the square method The polynomial x^28x16 is a perfect square (8/2)^2=16, so we need to add 16 to both sides of the equation and rearrange the terms Find The Equation Of The Circle Which Is Concentric With The Circle X 2 Y 2 4x 6y 3 0 And The Double Of Its Area The circle concentric with x^2+y^2+4x+6y+3=0